Until it intersects the Re=1 circle, then we can exactly match any impedance that does not have a reflectionĬoefficient magnitude equal to 1 (that is, we can match anything on the interior of the Smith Chart). Now, if we use a transmission line section to rotate the impedance on the Smith Chart Recall that if an impedance is of the form z1 = 1 + iX, then we can exactly match it using a series Impedance zL on the Smith Chart along with its constant VSWR circle. To any location in the black circular ring of Figure 1:įigure 1. That is, given the load impedance zL, a transmission line section can relocate the impedance That a transmission line section will enable the load impedance to move in a circle about the center of Suppose we use a transmission line section to move the impedance. Let's look at example 2 from the previous page again. We'll show how to use transmission line sections and a series component to exactly match any load impedance. This method won't work unless the real part of the load impedance is 1 (that is, Re=1). How to use series inductors and capacitors to cancel out the reactance of a load. The Smith Chart - Impedance Matching with Tx Lines, Series Inductors and Capacitors Smith Chart Tutorial - Impedance Matching with Tx Lines, Series L and C Previous: Series L and C
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